Zelensky congratulates Sanda on winning presidential elections in Moldova

The President of Ukraine Volodymyr Zelensky congratulated the leader of the Party of Action and Solidarity Maya Sanda on victory in the election of the head of Moldova. The statement is available on Zelensky’s page at Twitter .

“Congratulations to Maia Sanda on winning the presidential elections in Moldova. I look forward to further strengthening relations between Ukraine and Moldova for the European future of our peoples,” Zelensky wrote.

By data CEC Moldova, after processing 100 percent of the protocols, 57.75 percent of voters voted for Maia Sandu, and for her rival, the current president Igor Dodon 42.25 percent of citizens cast their votes.

Earlier on November 16, Sandu announced about her victory. “I am proud of my team and all the young people who took part in the vote,” she said.